Section 6.7 (p.362)

 

2.        

 

4.        

 

6.        

 

8.        

 

10.      

 

11.      

 

12.       (a)

 

            (b)

 

            (c)

 

            (d)

 

            (e)

 

            (f)

 

            (g)

 

            (h)

 

            (i)

 

13.       There exists a map f such that f(T) = T and f –1(T) = T. If T is a sufficient statistic, then by Factorization Criterion we have

Therefore, T is also a sufficient statistic. By the same token we can show that if T is sufficient then T is also sufficient.

 

14.       T = S log Xi = log (P Xi). That is, S log Xi is a one-to-one function of P Xi. From Exercise 6 and 14 we know that T = S log Xi is a sufficient statistic.