Section 6.7 (p.362)
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13. There exists a map f such that f(T) = T
‘ and f –1(T ‘) = T. If T is a sufficient
statistic, then by Factorization Criterion we have
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Therefore, T ‘
is also a sufficient statistic. By the same token we can show that if T ‘
is sufficient then T is also sufficient.
14. T = S
log Xi = log (P Xi). That is, S log Xi is a one-to-one function of P Xi. From Exercise 6 and 14 we know
that T = S log Xi is a sufficient statistic.